I need help with algebra 2 hw, adding and subtracting complex numbers? i forgot how to do them: 1. (2 +5i) + (?

Question

Please show workI need help with algebra 2 hw, adding and subtracting complex numbers?
i forgot how to do them:
1. (2 +5i) + (-2 + 5i)
2. 3(-1- 8i) + 2(4 + 3i)
3. (4 - 8i) + (-13 + 23 i)
4. (6 + 17 i) - (18 - 9i)
5. 2(1 - 3i) - 3(7 + i)
6. (-30 + i) - (-2 + 20 i)
Please show work

Answer 1

1.(2+5i)+(-2+5i)

=2+5i-2+5i

=0+10i

2.3(-1-8i)+2(4+3i)

=-3-24i+8+6i

=5-18i

similarly do your self

Answer 2

The mathematics book is proper. One method to suppose about it is to visualize a line in front of you with -three on the far left, and +three at the far proper, and the opposite numbers so as from left to correct (-3, -2, -1, zero, 1, 2, 3) including confident numbers method relocating towards the right, subtracting positive numbers means moving toward the left. Now think of the minus sign as a sign to go within the reverse path. So adding poor numbers means relocating in the direction of the LEFT, and subtracting poor numbers method moving in the direction of the proper. In case you at 1 and add +2, you progress to the proper 2 and get three. In the event you begin at 1 and subtract 2, you move to the left 2 and get -1. When you add -2 you transfer to the correct -2. The minus sign says reverse +2, so rather of relocating proper 2, you move left 2. When you subtract -2 you begin to maneuver to the left -2, but the minus tells you to move in the reverse course, so you progress correct 2 and end up with +3. Does that aid? Once you take delivery of that, you will see that that the minus indicators (one for subtract or transfer left and one for -2 or go opposite +2) cancel each and every different out. So 1 - -2 = 1 + 2 = 3.

Answer 3

1.) 2-2+5i+5i=10i

2.)-3+8i+8+6i=5+14i

3.) 4-13-8i+23i=-9+18i

4.) 6-18+17i+9i= -12+26i

5.) 2-6i-21+3i=-19-3i

6.) -30+i+2-20i=-28-19i

Answer 4

The critical thing to "remember" (know) is that a complex number

is made up of a real component and an imaginary(non-real)

component. [When you're dealing only with real numbers (in the complex,

number universe) the imaginary (non-real) component is virtually ignored.]



That said, the real numbers and non-reals are DISJOINT SETS; they share

no common element(s). 1) 10i

4) -12 +26i. Now you can do the rest.

Answer 5

they all easy .. you just add or subtract the corresponding real numbers and the imaginary parts



eg (a+bi) + (c+ di ) = (a+c) + (b+d) i

Answer 6

just add your real parts, then add your imaginary parts



I bet if you replaced all the "i"s with x you could do it! It is no more complicated than that.