What is Derivative of ln^2 ??HELP!?

Question

If derivative of ln=1/x and derivative ln2=1/2x what is derivative of ln^2?? There is no brackets. Please help. I know the answer is easy as cake,but i cant figure it out...

Answer 1

y = ln^2 x

dy/dx = 2 ln x • 1/x = 2 ln x/x

Answer 2

I suppose you mean this:



ln'(x) = 1/x

ln'(2x) = 1/x

ln'(x^2) = ?



ln'(x^2) = ln'(x) + ln'(x) = 1/x + 1/x = 2/x



For ln^2'(x):



Let t = ln(x)

y = t^2



ln^2'(x) = 1/x . 2t = 1/x . 2ln(x) = 2ln(x) / x

Answer 3

Try 0, see if it works... and you really should study derivatives.

Answer 4

d/dx(ln(2x)) =

2/(2x) =

1/x



d/dx(ln^2(x)) =...use the chain rule

2(lnx)(1/x) =

2lnx/x