Permutations and Combinations?

Question

Yes. I have looked on the internet for it. However, I still don't understand it. It'd be really great if you could help me understand.

So, here is the question:
In Alberta, Canada, they have a lottery system similar to the ones played here in America. However, instead of matching 6 numbers out of 42 possible, they match 5 out of 50 possible. Based on this change, calculate the total number of possible tickets based on the following restrictions:

(here is question number one, the others are similar, but I'm sure if I finally understand number 1, I can do that rest)

1. How many possible combinations would there be WITH replacement if ORDER MATTERS?

Thank you!

Answer 1

if order doesn't matter, it is a combinations problem: 50C5 = 50! / (45! * 5!) = 2118760.



if it's with replacement and order matters, it is 50*50*50*50*50

Answer 2

Isnt there a formula to calculate combination?

Answer 3

50!/(50-5)!



! = 50*49*48*. . . . *1