matrices for fun?

Question

find the adjoint of the following matrix:

3 2 -1
1 6 3
2 -4 0

have fun

Answer 1

3 1 2

2 6 -4

-1 3 0



Let's call YOUR matrix "A" and the adjoint matrix "A*"



Define elements of A [generally A(m,n)]as....



[A(1,1) A(1,2) A(1,3)]

[A(2,1) A(2,2) A(2,3)]

[A(3,1) A(3,2) A(3,3)]



i.e. A(1,1) = 3, A(3,2) = -4



The adjoint matrix "A*" is defined as.....



------------[A*(m,n) = A(n,m)]---------------



For example, A*(2,3) = A(3,2) = -4



Do this for the rest of the matrix elements and you will get my answer

Answer 2

LOL



You are a funny person!



Oh, hell, I just went and looked it up. See, I'm a math major, but I don't remember studying those...so here you go.



An adjoint matrix, as I'm sure you are well aware, is just the complex transpose of some given matrix. Since your entries are all real numbers, taking the complex conjugate doesn't make sense, so all you have to do is find the transpose, which is a reflection of entries across the main diagonal in a square matrix. This isn't very complicated...not so much fun either though.



3 1 2

3 6 -4

-1 3 0



That's it...unless I'm missing something. According to wiki, that is the complex transpose, or the adjoint, matrix.

Answer 3

i dont know nothing about adjoint matrix.