Factorise and Simplify 3a squared + 3a - 18?

Question

And also please explain how you go the answer, thank-you!

Answer 1

3a² + 3a - 18 = ( 3a - 6 ) ( a + 3 )



To check :

( 3a x a ) + ( 3a x 3 ) + ( -6 x a ) + ( -6 x 3 )

= 3a² + 9a - 6a -18

= 3a² + 3a - 18

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TAKE NOTE :

You are not solving for "a", because this is NOT an equation !!!

You just want to factorize & simplify the expression ,,,

Answer 2

3 a^2 + 3 a - 18

= 3 [ a^2 + a - 6] [ - 6= 3 x -2 and 3- 2 =1 ]

= 3 [ a^2 + 3a - 2a - 6 ]

= 3 [ a( a+ 3 ) - 2 ( a+ 3 ) ]

= 3 ( a+ 3 ) (a-2 ) answer

Answer 3

3a^2+3a-18 = 3 (a^2 +a-6)



= 3 (a+3 ) (a - 2)

Answer 4

3a^2 + 3a - 18



First factor out the "3". This leaves you with:



3(a^2 + a - 6)



Next, factor out the quadratic:



a^2 + a - 6 = (a + 3)(a - 2)



Finally regroup using all three factors and set equal to zero:



3(a + 3) (a - 2) = 0



a = -3

a = 2

Answer 5

3 (a² + a - 6)



3 (a + 3)(a - 2)