Two circles have the same center. The radius of the larger circle is 3 units longer than the radius of the smaller circle. Find the difference in the circumferences of the two circles. Round to the nearest hundredth.
Five answers:
Captain Matticus, LandPiratesInc
2010-07-12 13:47:37 UTC
R1 = r
R2 = r + 3
C1 = 2 * pi * r
C2 = 2 * pi * (r + 3) = 2 * pi * r + 6 * pi
C2 - C1 = 2pi * r + 6pi - 2pi * r = 6 * pi = 18.85
anonymous
2010-07-12 13:46:22 UTC
Let r be the radius of the smaller circle. Then the radius of the bigger one is r+3.
You know that C = 2 pi r, so the circumference of the smaller one is 2*pi*r and the circumference of the bigger is 2*pi*(r+3). Subtract the first from the second.
mather
2010-07-12 13:49:51 UTC
radius 1 = r
radius 2 = r + 3
C = 2 pi r
C1 = 2 pi r
C2 = 2 pi (r+3) = 2 pi r + 6 Pi
C2 is 6 pi larger or 18.85 units
weatherby
2016-11-16 08:52:27 UTC
do not hear to alan, he's a liar. this feels greater like a 5 to me. nicely at first something related to a letter could be skipped over, so 0A+4 (0a-8) = 4+0a A+4 (a-8) = 4+a so now we subtract 8 from 4 getting "4" A-4 = 4+a at this element the fours merge right into a single 4 A = 4+a as "a" is the 1st letter interior the alphabet, it equals "a million" so: A = 5
Ahmed Aba
2010-07-12 13:51:55 UTC
diff=2pi(r+3)-2pi(r)
2pi.r+6pi-2pi.r=6pi
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