The question "what are the elements of a group when taking the cross product" seems to presume that, given any operation, it is possible to make it the binary operation of some group. This is not the case. There are several problems with making the cross product the binary operation of a group. One is that the cross product is not associative. For example,
((1,0,0) x (0,1,0)) x (1,1,1) = (0,0,1) x (1,1,1) = (-1,1,0)
but
(1,0,0) x ((0,1,0) x (1,1,1)) = (1,0,0) x (1,0,-1) = (0,1,0).
[I chose the vectors (1,0,0), (0,1,0), and (1,1,1) almost at random--- it's certainly possible to find vectors u, v, and w that do satisfy (u x v) x w = u x (v x w), but most choices of u, v, w do not make this true. And we only need one example where it isn't true to know that x is not associative.]
Another issue is that there is not even a left identity element for the cross product--- that is, there is no vector u satisfying u x v = v for all v. (Clearly the zero vector cannot have this property, and if u is nonzero, then u x u = 0 is not the same as u.) And if there is no left identity element for a binary operation, there is no two-sided identity element for a binary operation, and no conceivable meaning that one can give to "inverses" with respect to this operation (as inverses are defined in terms of an identity element).
The lesson is that there are commonly used (and useful!) binary operations that do not easily fit into the framework of group theory. This is OK, though. Group theory is a very applicable subject, but it makes no claim to be a "theory of everything", and there is a lot of math that simply is not group theory. I hope this helped.