Question:
could someone help me solve this one word problem please?
anonymous
2014-02-23 11:39:21 UTC
just one word problem im stuck on.

"Helen sold 29 houses one month, and 15 houses the next month. How many houses must she sell in her third month for her average to be at least 22 houses per month?"
Five answers:
Andre
2014-02-23 11:51:34 UTC
Average or the mean (as some people may know it) is where you add the numbers up and divide by how many there are.

Since we're only talking about 3 months and we already have 2, it's just a simple bit of addition.

29 + 15 + x = 66

44 + x = 66

x = 22

Check: (29 + 15 + 22)/(3) = 66/3 = 22
anonymous
2014-02-23 11:43:28 UTC
First you have to find the number of houses you know which is 29 and 15. Then you add them together:

29+15= 44 (number of houses you know sold)



Then, you find what would be total of three homes if the average was 22 by multiplying 22 times 3:

22×3=66 (total houses sold)



Then you just subtract 44 from 66 and you get the answer:

66-44= 22



22 is the answer.



I hope I helped you understand!
William L
2014-02-23 11:43:21 UTC
Simple. Avg 22/mo x 3mos = 66. subject 29 and 15 from 66 = 22 in 3rd mo
?
2014-02-23 11:47:25 UTC
average = (∑x(i))/n



Let month1, month2, and month3 be the number of houses sold in the first, second, and third months, respectively.



average = (month1 + month2 +month3)/3



Now plug in the numbers that we have.



22 = (29 + 15 + month3)/3



Now solve for month3



22 = (29 + 15 + month3)/3

66 = 44 + month3

month 3 = 66 - 44 = 22 houses
?
2014-02-23 11:41:00 UTC
22

METHOD?

quite simple

(29+15+X)/3 = 22

44+X = 22*3

X= 66-44= 22


This content was originally posted on Y! Answers, a Q&A website that shut down in 2021.
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