Factor by Grouping. 2m+mn+6+3n?

Question

I am having trouble on the steps to solve this equation. I get the general idea

Answer 1

[2m+mn]+[6+3n] <-- Factor by grouping by taking a common factor out of each brackets.

m(2 + n)+ 3(2 + n)

(2 + n)(3 + m) <-- Final answer

Answer 2

1. 2m+mn+6+3n

2. m(2+n)+3(2+n)

3. (m+3)(2+n)

Answer 3

2m+mn+6+3n



(2m+mn)+(6+3n)



m(2 + n) + 3(2 + n)



(2 + n)*(m + 3).............ANSWER