Math Question. A regular polygon has n sides. The size of each interior angle is 4 times the size of each...?
anonymous
2007-08-07 07:35:39 UTC
A regular polygon has n sides. The size of each interior angle is 4 times the size of each exterior angle.
Calculate the size of each interior angle.
Hence, find the value of n.
Five answers:
sahsjing
2007-08-07 07:44:41 UTC
Let the size of each exterior angle be x. Since any interior angle is supplementary to its corresponding exterior angle, we have
4x+x = 180
Solve for x,
x = 36
4x = 144 deg, the size of each interior angle.
n = 360/36 = 10 sides
gfulton57
2007-08-07 07:45:07 UTC
The sum of an angle and its exterior angle always equals 180 degrees. Since the interior angle is 4 times the exterior, we can let x be the exterior and 4x equal the interior angle.
So x + 4x = 180 or 5x = 180 and x = 36 (the exterior angle)
and 4x = 144 degrees (interior angle)
also, the sum of the exterior angles is always 360 degrees
so the total of 360 divided by 36 gives 10 sides from the formula 360 / n = measure of one exterior angle.
bleh.
2007-08-07 07:40:55 UTC
180 / 5 = 36 (the exterior angle)
36 X 4 = 144 (interior angle)
the value of n is 10. but unsure on how to describe. sorry
?
2016-05-21 02:39:39 UTC
a) Given: regular polygon with n sides Let 360deg/n = size of each exterior angle 8(360deg/n) = size of each interior angle. ext. angle + int. angle = 180 deg 360/n + 8(360/n) = 180 9(360/n) = 180 3240/n = 180 n = 3240/180 n = 18 ANS 360/18 = 20 deg, size of each exterior angle teddy boy
anonymous
2007-08-07 07:46:09 UTC
e = exterior
i = interior
1) e + i = 180 (exerior + interior angle must = 180)
2) 4i = e (from your question)
5i=180 (Sub 2 into 1)
i = 36
From the attached link,
360/36 =10 sides.
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