Write the expression as a complex number in standard form.?

Question

1. (3+2i) + (-5+8i)
2. (-2-4i) + (3-6i)
3. (4+2I) - (-1+5i)
4. (5-8i) -(2+9i)
5. (5-4i)(3+6i)
6. (2+5i)^2
7. 6/ 2+3I)
7. 3+i/ -2+i
Need help with writing these problems as a complex number in standard form.

Answer 1

see here.

http://www.purplemath.com/modules/complex2.htm

Answer 2

You can just remove the parenthesis and simplify by gathering like terms and you go from 3 - 9i + 4 + 5i = 3 + 4 + 5i - 9i (commutative property of addition) = 7 - 4i

Answer 3

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RE:

Write the expression as a complex number in standard form.?

1. (3+2i) + (-5+8i)

2. (-2-4i) + (3-6i)

3. (4+2I) - (-1+5i)

4. (5-8i) -(2+9i)

5. (5-4i)(3+6i)

6. (2+5i)^2

7. 6/ 2+3I)

7. 3+i/ -2+i

Need help with writing these problems as a complex number in standard form.

Answer 4

1. (3+2i) + (-5+8i)

=-2+10i answer//



2. (-2-4i) + (3-6i)

=1-10i answer//



3. (4+2i) - (-1+5i)

=4+2i+1-5i

=5-3i answer//



4. (5-8i) -(2+9i)

=5-8i-2-9i

=3-17i answer//



5. (5-4i)(3+6i)

=15-12i+30i-24i^2

=15+18i-24(-1)

=15+18i+24

=39+18i answer//



6. (2+5i)^2

=(2+5i)(2+5i)

=4+20i+25i^2

=4+20i-25

=-21+20i answer//



7 ..6.........2-3i

..-----------x-----------

...2+3i........2-3i



....12-18i

=---------------

....4-9i^2



....12-18i

=-------------

..... 4+9



.....12+18i

=--------------- answer//

........13





8...3+i...........-2-i

---------------- x---------

....-2+i...........-2-i



....-6-3i-2i-i^2

=--------------------

....4+2i-2i-i^2



....-6-5i+1

=---------------

.....4+1



....-5-5i

=----------

......5



=-1-i answer//

Answer 5

i hope im right...



1. -2+10i

2. 1-10i

3. 5-3i

4. 3-17i

5. 39+18i

6. -21+20i

7. (12-18i) / 13

8. -1-i or -(1+i)

Answer 6

1. -2+10i

2. 1-10i

3. 5-3i

4. 3-17i

5. 39+18i

6. -21+20i

7. i'm asumming is 6/(2+3i) and 12/13-18/13i or .923...-1.384...i

8. i'm asumming is (3+i)/(-2+i) and -1-i

Answer 7

in standard form it's a + bi (where a & b are integers). so you would need to do some algebra. for 1, 2, 3, and 4, you can just do simple addition/subtraction (but remember to multiply the negative signs outside of the parenthesis all the way through in #s 3 &4). 5 and 6 are tricky because they use FOILing. and the last two might need to be manipulated some before you get it in a non-fraction form.