A vertical parabola is of the form y=x^2. A horizontal is of the form x=y^2
?
2016-08-04 10:03:55 UTC
We simply did this in these days. Adequate, the commonplace parabola form is x²=4py, with p equalling both the asmptote and the focus. The course is recognized by means of whether or not x² or y² is first; if it is x²=4py, the parabola is vertical. If it is y²=4px, it can be horizontal. Whether or not it goes up, down left or proper will depend on if p is positive or terrible; positive makes it go up or correct (depending on whether it can be hori or vert) and bad makes it down or left. So, for those who had x²=12y, your focus would be (zero, four) and your asymptote can be x=-four. It might be vertical and opening up.. The vertex is regularly the beginning (zero,zero); if no longer, it follows the form (y-y1)²=4p(x-x1). Nevertheless, converting your equation to commonplace has to do with utilizing vertex type, which we've not learned yet. I am hoping what I gave you so far helps though.
lia l
2013-07-28 02:28:07 UTC
y=k(x-0)^2-2
since it goes through the point (3,4)
4=k(3)^2 -2
k=6/9=2/3
The equation of parabola is y=(2/3)x^2-2
it is vertical
Ryan
2013-07-28 02:01:01 UTC
you need more information, two points form a line and could possible form either a vertical or a horizontal parabola
A related equation
Boundary conditions
You need something else
anonymous
2013-07-28 01:59:42 UTC
put in the equation of horizontal and vertical parabola ... if it satisfies ,it would be that one ..
?
2013-07-28 02:13:08 UTC
With the information given,it can be either. Just one more point needed.
Heaven Convergence
2013-07-28 02:08:16 UTC
Generally according to vertical if there is solution.
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