Team X and Team Y have a tug of war. From their starting positions team X pulls team Y forward 3 meters, and are then pulled forward themselves 5 meters. Team Y then pulls team X forward 2 meters. If the first team to be pulled forward 10 meters loses, how many more meters must team Y pull team X forward to win?
Please explain the answer, no one in my family got the answer. Thanks!!
Five answers:
ignoramus
2012-09-23 13:05:34 UTC
In any tug-o-war that I have participated in, the losing team has to be pulled a certain distance forward FROM THE STARTING POINT.
If that is the case in this instance, then
a) team X pulls Y forward 3m, therefore X's position is X - 3.
b) team Y pulls X forward 5m, therefore X's position is now X - 3 + 5
c) team Y pulls X forward another 2m, therefor X's position is X - 3 + 5 + 2 = X + 4.
That means that X is 4m in front of the starting position. So they must be pulled another 6m if Y is to win.
Kayleigh aka MoNkEy
2012-09-23 12:04:45 UTC
doesnt team Y have to pull 3 more meters? cos they already pulled 7 meters and if u add the 3 meters that team x pulled, it wpuld be equal to 10? not sure. just gave it a shot
2012-09-23 12:03:08 UTC
First team y are pulled 3 metres. Then team x are pulled 5 and 2 metres which equals 7metres there team y must pull team x another 3 metres. The answer is 3 metres.
?
2012-09-23 12:05:30 UTC
if u use a time line, u get 0 meters, 5 plus 3 then plus 2 equals ten.
James
2012-09-23 12:01:36 UTC
you're confusing the hell out of me!!!!
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