Word Problem?

Question

Team X and Team Y have a tug of war. From their starting positions Team X pulls Team Y forward 3 meters, and Team X is then pulled forward 5 meters. Team Y then pulls Team X forward 2 meters. If the first team to be pulled forward 10 meters loses, how many more meters must Team Y pull Team X forward to win?

Answer 1

Start with X being the initial position of team x. AFter each move, the equation is the position of x relative to the start.



x

x+3

x+3-5

x+3-5-2 = x-4



So team x has lost 4 meters to team y. That means y must get 4 more meters to win.

Answer 2

Lets make Team Y pulling Team X forward positive and

Lets make Team X pulling Team Y forward negative



1)Team X pulls Team Y forward 3 meters

total = -3

2)Team X is then pulled forward 5 meters

total = -3 + 5 = +2

3)Team Y then pulls Team X forward 2 meters

total = 2 + 2 = +4



We need 6 more meters

Answer 3

so lets see how much team x is pulled forward by now...

at first they have -3 meters...

then -3 + 5 = 2

then 2 + 2 = 4



so u just nid to pull team x .. 10 - 4 = 6 meters forward to win

Answer 4

Let positive be in the X direction and negative in the Y direction.



+3 - 5 - 2 = -4



Y now need to pull X a further 6m.

Answer 5

The Answer Is Non-Existent, I think.



Because Dont You Need To Know How Far Away They Are To The Middle?