Question:
One number is seven less than another. Their sum is eleven. Find the numbers.?
anonymous
2011-10-06 19:21:59 UTC
ANOTHER QUESTION IS
One number is eight more than twice another. If their sum is decreased by ten, the result is thirteen. Find the numbers.
LOOKING FOR BEST ANSWER!!!!
Five answers:
Brad
2011-10-06 19:43:49 UTC
You could always guess and check on problems like these, but an easy mathematical way would be to plug it into a "system of equations" :

Let's say one number is x,

And another number is y,

One number is 7 less than another:

X = y - 7

Where y is "less than" or just subtract by 7,

their sum is eleven

X + y = 11

so your system is:

X = y - 7

X + y = 11

Now, the next step is to isolate a single variable in either equation...

This is already done for you, notice how x is alone in this equation: X = y - 7 this allows you to plug it into the second equation using only 1 variable

Since x = y - 7

(y - 7) + y = 11

now just solve for Y!

2y - 7 = 11

2y = 18

y = 9

Now plug your new y into the original equation

X = 9 - 7

X = 2

Your numbers are 9 and 2

Q#2:

X = 2y + 8

(x + y) - 10 = 13

((2y+8)+y) - 10= 13

(3y + 8) - 10 = 13

3y - 2 = 13

3y = 15

y = 5

x = 2(5) + 8

x = 10 + 8

x = 18

Your numbers are 18 and 5,

This system takes a little work but it will give you a system to find proven correct answers... ( and it helps you in later math courses )
?
2016-03-02 02:28:24 UTC
Full working out - process of elimination It seems likely there are either only two possible answers or of those possible only two use all the digits between them without repetition. 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 lowest two digit number is 10, highest is 98 23 & 37 e.g. are prime numbers - useful if ending in seven is required as it reduces choices all available numbers: 10, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 56, 57, 58, 59 60, 61, 62, 63, 64, 65, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98. One of these is the required number ending in seven 17, 27, 37, 47, 57, 67, 87, 97 & as well as those others listed it also cancels use of 7, 70, 71, 72, 73, 74, 75, 76, 78, 79. It seems likely you should start looking at the number ending in seven. So of the non repeating two-digit numbers, 17 & 34, 17 & 68 17 & 85 27 & 54, 27 & 81 57 & 19 87 & 29 only a) 34 \ 17 = 2, b) 68 \ 17 = 4 c) 81 \ 27 = 3 d) 57 \ 19 = 3 e) 87 \ 29 = 3 have non repeating answers. Then, a) 12347, leaves 56890 b) 14678 leaves 23590 c) 12378 leaves 45690 d) 13579 leaves 24680 e) 23789 leaves 14560 ...which should now already start becoming obvious for a) 56890, 98, 96, 95, 90 89, 86, 85, 80 69, 68, 65, 60 59, 58, 56, 50 for b) 23590 95, 93, 92, 90 59, 53, 52, 50 39, 35, 32, 30 29, 25, 23, 20 for c) 45690 96, 95, 94, 90 69, 65, 64, 60 59, 56, 54, 50 49, 46, 45, 40 for d) 13579 97, 95, 93, 91 79, 75, 73, 71 59, 57, 53, 51 39, 37, 35, 31 19, 17, 15, 13 for e) 23789 98, 97, 93, 92 89, 87, 83, 82 79, 78, 73, 72 39, 38, 37, 32 29, 28, 27, 23 ...Of which the easiest ones to look at end in 0 and can not be a multiple of ten (9 & 90, 2 & 20), nor can any nuber be divided by one ending in 0 as it would also have to end in zero: __ \ ?0 is only a whole number for ?0 \ ?0 which is repetition. a) 56890, 98, 96, 95, 90 89, 86, 85, 80 69, 68, 65, 60 59, 58, 56, 50 using 90 leaves only 86, 85, 68, 65, 58, 56 - none are factors. - Immediately you can say the same for 80, 60 & 50 as the two digit numbers required are 40, 30, 25, 20, 15, & 12 b) 23590 95, 93, 92, 90 59, 53, 52, 50 39, 35, 32, 30 29, 25, 23, 20 using 90 leaves 53, 53, 35, 32, 25, 23 - none are factors for 50, 30 & 20 you need 25, 15, 10, none are factors or have repetition for c) 45690 96, 95, 94, 90 69, 65, 64, 60 59, 56, 54, 50 49, 46, 45, 40 for 90, 60, 50 & 40 you need 45, 30, 25, 20 & 10 which is almost promising to yield but for the fact 90 \ 45 = 2 & 2 is not in the set Then we look for any numbers that are primes - if their multiples are available all between 0-100 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 for a) 56890, 98, 96, 95, 90 89, 86, 85, 80 69, 68, 65, 60 59, 58, 56, 50 so 89 & 59 are both factors only of at least three digit numbers for b) 23590 95, 93, 92, 90 59, 53, 52, 50 39, 35, 32, 30 29, 25, 23, 20 so 59, 53 not allowed, 29 needs 58 or 87, 23 needs 46, 69 or 92 for c) 45690 96, 95, 94, 90 69, 65, 64, 60 59, 56, 54, 50 49, 46, 45, 40 so just 59 & not allowed for d) 13579 97, 95, 93, 91 79, 75, 73, 71 59, 57, 53, 51 39, 37, 35, 31 19, 17, 15, 13 so 97, 79, 73, 71, 59, 53 all at least three digit multiples 37, 31, 19, 17 & 13 need 74, 62, 93, 38, 57*, 76, 95, 34, 51, 68, 85, 26, 39, 52, 65, 78, 91 *of which 57 \ 19 = 3 is the only answer :) won't bother with this then for e) 23789 98, 97, 93, 92 89, 87, 83, 82 79, 78, 73, 72 39, 38, 37, 32 29, 28, 27, 23
anonymous
2011-10-06 19:32:26 UTC
Let x = one number

Let y = the other number



"One number is seven less than another" translates to:

x = y-7

x-y = -7



"Their sum is 11" translates to:

x+y = 11



Add the two equations vertically.

x-y = -7

x+y = 11

-------------

2x = 4



2x = 4

x = 4/2

x = 2



Now that you know the value of x, plug that into either of the two equations.

x+y = 11

(2)+y = 11

y = 11-2

y = 9



Answer: 2 and 9

___________________________________________________________



Let x = one number

Let y = the other number



"One number is eight more than twice the other" translates to:

x = 2y+8

x-2y = 8



"If their sum is decreased by 10, the result is thirteen" translates to:

(x+y)-10 = 13

x+y = 13+10

x+y = 23

But now I'll multiply both sides of the equation by -1 because I want to be able to cancel out the x's when I add the two equations vertically.

(-1)(x+y) = (-1)(23)

-x-y = -23



Add the two equations vertically.



x-2y = 8

-x-y = -23

--------------

-3y = -15



-3y = -15

y = -15/(-3)

y = 5



Now that you know the value of y, plug that into either of the two equations.

x = 2y+8

x = 2(5)+8

x = 10+8

x = 18



Answer: 5 and 18
egyptiankitty590
2011-10-06 19:24:06 UTC
First one: 2 and 9 (2+9=11; 9-2=7)
Mike G
2011-10-06 19:24:08 UTC
(i) N+N-7 = 11

2N-7=11

2N=18

N=9

Numbers are 9 and 2



(ii) A = 2B+8

A+B-10=13

2B+8+B-10 = 13

3B = 15

B = 5

A = 18


This content was originally posted on Y! Answers, a Q&A website that shut down in 2021.
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