Fill in the blanks in this sequence with as many solutions as you can.
So far I got: 1/4, 1/16 or 4 and 16
Six answers:
2007-11-17 13:57:01 UTC
1 (= 64/64), then 43/64, 22/64, and 1/64 - decreasing by 21/64 each time.
Or 1 (= 64/64), then 57/64, 36/64, 1/64 - decreasing by 7/64, 21/64 and 35/64 which increase by 14/64 each time.
I think the teacher will get suspicious if you turn in anything more complicated than your own solution and these two.
DWRead
2007-11-17 21:33:23 UTC
The series appears to be 1/(4^(n-1)), for n = 1, 2, 3,...
1/4⁰, 1/4¹, 1/4², 1/4³
So all you have to do is calculate 1/4¹ and 1/4², then simplify.
SaintPretz59
2007-11-17 21:34:21 UTC
Tell you teacher that there are infinitely many sequences.
This "function" has the "points"
(1,1) and (4,1/64)
you can connect those points with a line, infinitely many parabolas, infinitely many cubic functions, sine functions, geometric sequences (as in, divide by 4 each time).... make some up! There are infinitely many numbers for the 2nd and third space.
If you're interested in finding some actual such equations (or rules) then you can email me at stalepretzel@gmail.com
2007-11-17 21:25:34 UTC
Its 1/4 and 1/16
You just divide by 4 every time
claudiacake
2007-11-17 21:27:29 UTC
1/16, 1/32
sv
2007-11-17 21:48:52 UTC
1, .... , .... , 1/64, ....
= 4^0, 4^(--1), 4^(--2), 4^(--3), 4^(--5), ....
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