Help finding the area between two similar triangles?

Question

The area of the smaller of two similar triangles is 1/9 the area of the larger triangle.

Suppose one side of the smaller triangle is 3.6. What is the length of the corresponding side of the larger triangle?

Suppose one side of the larger triangle is 36. What is the length of the corresponding side of the triangle?

I really need help. I tried this 5 different times and came up to the wrong conclusion everytime. Please help!

Answer 1

Ff ratio of areas is 1/9 then ratio of side lengths = sqrt(1/9) = 1/3



Hence:

a) 3 * 3.6 = 10.8

b) 1/3 * 36 = 12

Answer 2

similar triangles mean that each and every thing about the triangle is an same except for the size. this suggests they have a similar angles interior a similar order. So the ratio of the aspects will be equivalent to the ratio of similar aspects. so in case you had a small triangle with aspects a, b, and c and a higher triangle with aspects, A,B, and C respectively then the ratio of the realm ought to = a/A yet it really is barely for similar triangles, for different triangles you may locate the realm of both and then study, the realm for a triangle is one 1/2 the bottom cases the precise a million/2*b*h note: the precise isn't between the perimeters except in a suitable triangle

Answer 3

1) 1/9x=3.6

x= 32.4



2) 36x1/9

= 4