Bansi has 3 times as many 2 rupees coins as he has 5 rupees coins.If he has in all a sum of rs 77.How many...?

Question

coins of each denomination does he have ?

Q2) Deveshi has a total of Rs 590 as a currency notes in the denomination Rs50,Rs20,andRs10.The ratio of the number of Rs 50 and Rs 20 notes is 3:5.If she has a total of 25 notes.How many notes of each denomination has ?

Please answer both question

Answer 1

let the 5 Rs coin be x

Then the 2rs coin be 3x

Total amuont

from Rs 5=5*x=5x

from Rs2=2*3x=6x

Total=6x+5x=11x

sum os all rs=77

A/q

11x=77

x=77/11

x=7

The 5 Rs coin =x=7

Then the 2rs coin =3x=3*7=21



let the number of notes be x

let the no. of notes of rs 50 be 3x

let the no. of notes of rs 20 be 5x

but she has total no of notes =25

then no. of notes of rs 10=25-(5x+3x)

=25-8x

total amount from

Rs 50=50*3x=150x

Rs 20=20*5x=100x

Rs 10=10*(25-8x)=250-80x

hence total amount=170x+250

total currency is 590 rs

A/q

170x+250=590

170x=590-250

170x=340

x=340/170

x=2

the no. of notes of rs 50 is 3x=3*2=6

the no. of notes of rs 20 is 5x=5*2=10

no. of notes of rs 10=25-8x=25-8*2

=25-16

=9

Answer 2

Q1)Bansi has 3 times as many 2 rupees coins as he has 5 rupees coins.If he has in all a sum of rs 77.How many...? :



if he has 3 times more rs2 than rs5,

then ratio is 3:1

so thats rs6+rs5= 11rs

rs77/rs11 = 7



therefore he has:



7x3 = 21 (rs2)

and

7x1 = 7 (rs5)



Q2) Deveshi has a total of Rs 590 as a currency notes in the denomination Rs50,Rs20,andRs10.The ratio of the number of Rs 50 and Rs 20 notes is 3:5.If she has a total of 25 notes.How many notes of each denomination has ?



ratio of rs 50 to rs 20 is 3:5

therefor:

50x3 = 150

20x5 = 100

therefor;

150+100 = 250



total of Rs = 590



now:



590/250 = 2 remainder 90



this shows you have:

9 (RS 10)

5x2 = 10 (RS 20)

3x2 = 6 (RS 50)



if you have more of either the RS 20 or RS 50 notes it will ruin the ratio.



you are welcome

Answer 3

permit the style of money be X. The on the beginning up there have been X, a million rupee money and its fee is a million.X rupees, X, 2 rupee money and its fee is two.X rupees X, 5 rupee money and its fee is 5.X rupees as quickly as the 5 rupee money removed from the gadget, then the soundness is Rs one hundred and five and is largely a million and a couple of Rs money So a million.X + 2.X = one hundred and five 3 X = one hundred and five X = 35 for this reason the gadget contained 35 equivalent variety of money of a million Rs 2 Rs & 5 Rs

Answer 4

2 Rupee Coin

Answer 5

Q1) Let the number of Rs.5 coins be x.

value of these coins is = Rs.(5x)

number of Rs.2 coins = 3x

value of these coins = Rs.(6x)

Form an equation as follows,

5x+6x=77

Solve it and you will get the answer as,

Rs.2 coins = 7

Rs.5 coins = 21



Q2) Let the common measure be x.

Ratio=3x:5x

Form an equation as follows,

150x+100x+10(25-8x)=590

250x+250-80x=590

Solve it and you will get the answer as,

Rs.10 notes= 9

Rs.20 notes= 10

Rs.50 notes= 6

Answer 6

T is the number of two rupee coins and F is the number of 5 rupee coins

T = 3F

2 T + 5F = 77

substituting for F

2(3F) + 5F = 77

11 F = 77

F = 7

T = 21



Q2)

R50 + R20 + R10 = 25 : eqn 1

50 R50 + 20 R20 + 10 R10 = 590 or 5 R50 + 2 R20 + R10 = 59 : eqn 2

R50 / R20 = 3/5: R50 = 3/5 R20 : eqn 3

substituting into 2nd eqn

5 R20 + R10 = 59

substituting eqn 3 into eqn 1

8/5 R20 + R10 = 25

subtracting

(5 - 8/5) R20 = 34

17/5 R20 = 34

R20 = 170/17 = 10

5(10) + R10 = 59

R10 = 9

R50 + 10 + 9 = 25

R50 = 6



R50 = 6

R20 = 10

R10 = 9

Answer 7

If 5 rs coins = x, then 2 rs coins = 3x.

Total amount = 6x + 5x = 7x = 77 => x = 7.

=> 5 Rs coins = 7, 2 Rs coins = 21.

Answer 8

who cares he's Indian