(sq rt of x) (x - sq rt of x) Please!?

Question

All right, I got
x(sq rt x) - x
but it doesn't look right. There has to be some relationship between x and sq rt of x that I'm missing. Please help!

Answer 1

Remember, √x = x^1/2



(√x)(x-√x)



= x√x - √x^2



=x(x^1/2) - x



=x^(3/2) - x

Answer 2

Square root is the 1/2 power. Though you can't add x and sq rt of x, you can simplify the first factor:



Write x(sq rt x) as x[x^(1/2)], notation for x times x to the 1/2. To multiply powers you add the exponents, 1 + 1/2, so the exponent of the first factor is 3/2 thus you get



x to the 3/2 power for the first factor.

Answer 3

25^x=sq rt 5; rewriting, (5)^2)^x=5^1/2, or,(5)^2x=5^1/2, or,2x=1/2, x=1/4 answer 16^x=1/sq rt 2 re writing, (2)^4)^x=2^-1/2 , or,2^4x=2^-1/2 or 4x=-1/2, x=-1/8

Answer 4

well (sq rt of x) is the same as (sq rt of x +0)



so (sq rt of x +0) (x - sq rt of x)



so use the whole FOIL thing (first outside inside last)



(sq rt of x times x) (sq rt of x times -sq rt of x) (0 times x) (0 times -sq rt of x)



which simplifys to what youve got. looks right to me

Answer 5

You're right. It is x(sq rt (x)) - x = x*(sq rt (x) - 1).

Answer 6

sqrt(x) * (x - sqrt(x)) = x*sqrt(x) - x

You are right about that.



It can be written with exponents.

sqrt(x) can be written as x^(1/2)

x*sqrt(x) = x*x^(1/2) = x^(1 +1/2) = x^(3/2)

Is that what you're looking for?

Answer 7

(sq rt x)(x-sq rt x)

=sq rt x.x-(sq rtx)(sq rtx)

= x sq rt x-x ans

Answer 8

You can go one step further:



x(sqrt(x) - 1)



But that's about it.

Answer 9

only other thing you could do is x*(sqrt(x) -1)



if you missed something... well i guess I missed it too ! :-)

Answer 10

oh that's minus.