in one day a store sold 8/5 as many cups as plates. The total number of cups and plates sold that day was 273.?

Question

in one day a store sold 8/5 as many cups as plates. The total number of cups and plates sold that day was 273. How many cups and plates were sold?

Answer 1

cups:plate = 8:5 every 8 cups join 5 plates 8/5=1.6 .. assume that Cups are c and plates are p

c=1.6p

c+p=273

2.6p=273

p=105 plates

c= 1.6*105=168 cups

check c+p=273....105+168=273.. wish that helps

Answer 2

Let x= the number of plates sold

so (8/5)x = number of cups sold



If the sum of the two are 273 then the equation becomes:

x + (8/5)x = 273



(13/5)x = 273 <=== Multiply both sides by the reciprocal of 13/5

(5/13)(13/5)x = (273)(5/13)

x = 105



So Plates = x = 105

cups = (8/5)(105) = 168

Answer 3

For every 8 cups , 5 plates were sold. So total = 8+5 = 13



273/13 = 21



So cups = 21 x 8 = 168

plates = 21 x 5 = 105 ANSWER



Check your answer

105 + 168 = 273

168/105 = 8/5

Answer 4

The ratio for cups and plates is 8:5. If there was 8 cups, there would be 5 plates and so on. If there was 8 cups, there would be 5 plates, there will be 13 cups and plates. Lets call every 13 cups and plates, 1 group.



273 is the total number of cups and plates. Divide 273 by the 13 (cups and plates) and you'll find the number of groups. The number of groups is 21.



There are 21 groups. if we times it by 13, we'd get 273 again. (13 is the total)



if we times it by 8 (number of cups out of 13), we'll get the number of cups =

168



if we times it by 5 (number of plates out of 13), we'll get the number of plates =

105 plates



FINAL ANSWER = 168 Cups and 105 Plates

Answer 5

168 cups

105 plates



If they sold 8/5ths as many cups as plates. Then they sold 5/5ths as many plates. In all there were 8/5ths + 5/5ths items sold. Totalling 13/5ths. So 273 represents 13/5ths so 1 fifth is found by dividing it by 13 which is equal to 21.



So 8/5 = 8x21 = 168

and 5/5 = 5x 21 = 105

Answer 6

c = (8/5)p



c + p = 273

(8/5)p + p = 273

(8/5)p + (5/5)p = 273

(13/5)p = 273

p = (5/13)(273) = 105

c = (8/5)*105 = 168



168 + 105 = 273

Answer 7

(8/5)x+x = 273

(8/5)x + (5/5)x = 273

(13/5)x = 273

x = (5/13)(273) = 105 = no.of plates

ans no.of cups = 168

Answer 8

properly, to remedy this concern, we could provide each and every cup a variable. we are going to call plastic cups bought "x" and ceramic cups bought "y". we are going to remedy this by utilising structures of equations, with has us make 2 equations and see the place they intersect. If 500 cups have been bought, meaning that the form of plastic cups plus the form of ceramic cups bought replaced into 500, so x + y = $500; if the cups bought for $2,090, then you extremely could set it up like 3.25 * x + 4.50 * y = $2,090 so then merely remedy. to remedy, we could isolate y in the two equations to place right into a calculator (sooooo lots much less annoying than fixing by utilising hand) and calculate the intersect (2nd, calculate, intersect line up flashing dot to the intersection factor and press enter thrice). To set y by utilising itself in the 1st equation you subtract x from the two factors supplying you with y = 500 - x. the 2nd is extra sturdy, yet nevertheless tremendously basic. you subtract 3.25x from the two side and divide by utilising 4.50 to supply you y = ( -3.25x + 2,090 ) / 4.50. then merely calculate the intersect.