Identify the line that contains the error in this solution and correct the work for that line?

Question

I need help asap.

Line 1: -2 (x+1) - 3 greater than or equal to 11
Line 2: -2x + -2 - 3 greater than or equal to 11
Line 3: -2x + -5 greater than or equal to 11
Line 4: -2x less than or equal to 16
x less than or equal to -8

Thanks. :) I appreciate the help.

Answer 1

Line 4 is your error.



If you add 5 to both sides, that does not alter the direction of your aniquality.



It should be:



-2x greater than or equal to 16



Then dividing both sides by -2 switches the direction:



x is less than or equal to -8.

Answer 2

The final answer is correct, but you have two errors which counteract each other. The step from Line 3 to Line 4 is in error. You only reverse the direction of the inequality when you multiply or divide by a negative number, not when you add or subtract.



Line 3: -2x + -5 ≥ 11

Line 4: -2x ≥ 16 (corrected)

x ≤ -8



The step from line 4 to the last, unnumbered line is also in error. If line 4 were correct, then when you divide by -2, you would have to reverse the direction of the inequality. But, that error reverses the error in line 4 such that you wind up with the correct answer for the overall problem,

Answer 3

Answer is line 4



it should be -2x greater that or equal to 16, we just add add 5 on both sides so there is no need to reverse the sign

Answer 4

Line 4 is wrong because you don't reverse the inequality when adding or subtracting from both sides of an inequality.

Line 5 is wrong because you do reverse the inequality when multiplying or dividing both sides of an inequality by a negative number.



Correct way:

line 3: -2x - 5 ≥ 11

line 4: -2x ≥ 16

line 5: x ≤ -8

Answer 5

Ljne 5 is the incorrect line.

When you divide Line 4 by -2 you must reverse the <= sign to >= because the number you are dividing by is negative.