How is this algebra 1 problem solved?

Question

This is called Graphs of Linear Equations.
I have to construct a graph with the following: 8x -3y = -6.
What are my points to plot?

Thank You.

Answer 1

Pick some!

Rearrange the equation so that you get 3y = 8x + 6.



Then try say x = 3. This gives you y = 10. Plot that.

Then try say x = 0. This gives you y = 2. Plot that.

Then try say x = 6. This gives you y = 18. Plot that.



Then draw a straight line through the points (and beyond in both directions) and that's your graph.



You can do this with any linear equation, get it in the form ay = bx + c

(where a,b,c are numbers) and just pick some numbers. Once you have two points you can plot the graph, but it's always good to plot a third point first :D



If you need any more explanation, edit your post and I'll add more detail.



Hope I helped.

Answer 2

well, your if u put the equation in linear form u get: y= 8/3x+2.

All you do is plug in values for x in the linear equation and come out with a y value.

Here are some:

plug in 0 for x: y= 8/3*0+2 the point would be (0, 2)

Thats all you have to do.

Answer 3

You need at least two points.



Substitute 0 in for x, solve for y...y=2

Substitute 0 in for y, solve for x...x= -3/4



There are your two points:

(0, 2)

(-3/4, 0)

Answer 4

8x - 3y = -6

-8x -8x

---------------------

-3y = -8x - 6



m= -8 8

----- or ------

1 -1



b= -6