the length of the top of a table is 4m greater than the width. The area is 60 m^2.?

Question

Find the dimensions of the table

Width =

Length-=

Answer 1

Hi,



Width = 6 m



Length = 10 m



If the width is x meters, then the length is x + 4 meters. The area 60 m² is found by:



x(x + 4) = 60

x² + 4x = 60

x² + 4x - 60 = 0

(x + 10)(x - 6) = 0

x + 10 = 0

x = -10 but since a side can not have a negative length, discard it.



x - 6 = 0

x = 6 so the width is 6 meters.

The length is 4 more than the width or 10 meters.



The table is 10 meters by 6 meters. <== ANSWER



I hope that helps!! :-)

Answer 2

Let w be the width of the table.

Then w + 4 is the length of the table.

and A = 60



So using the area formula... L * W = Area ....



(w + 4) * w = 60



w^2 + 4w = 60

w^2 + 4w - 60 = 0

(w + 10)(w - 6) = 0 ... factor



Use the zero factor theorem to solve...



w + 10 = 0 , or w - 6 = 0

w = -10 , or w = 6



Since width cannot be a negative number... your width must be 6.



So if w = 6 ... then length must be 6 + 4 which is 10.



Width = 6m

Length = 10m

Answer 3

Let the length of the table be denoted by L. Let the width of the table be denoted by W. By given: L = W + 6. Area table = L*W = (W + 6)*W = W^2 + 6W = 91. W^2 + 6W = 91 W^2 + 6W - 91 = 0 (W - 7)(W + 13) = 0 W = 7 m (accepted). W = - 13 m (rejected). L = W + 6 = 7 + 6 = 13 m. Then, the width of the table is 7 m and the length of the table is 13 m. GOD bless you...

Answer 4

Area = length * width = 60



and



length = width + 4



so



60 = width * (width + 4)



60 = (width)^2 + 4(width)



0 = w^2 +4w - 60



0 = (w + 10)(w - 6)



w = -10 or 6



6 is the only "real" answer



So,



width = 6m

length = 10m

Answer 5

w(w+4) = 60

w² +4w - 60 = 0

(w-6)(w+10)

w= 6 or w = -10

w = 6



width = 6 m

length = 10 m



hope that helps!!!

Answer 6

w=6m

L=10m