Question:
If at least 1 wuzzle is grumpy, then some fuzzles are lumpy.?
a
2009-08-01 20:21:49 UTC
If the statement above is true, then which of the following must also be true?

a. If all wuzzles are grumpy, then all fuzzles are lumpy.
b. If no wuzzle is grumpy, then all fuzzles are lumpy.
c. If all fuzzles are lumpy, then all wuzzles are grumpy.
d. If no wuzzle is grumpy, then no fuzzle is lumpy.
e. If no fuzzle is lumpy, then no wuzzle is grumpy.
Four answers:
s_h_mc
2009-08-01 20:31:28 UTC
What you have is a conditional statement, if this then that, if p then q.

The contrapositive of a conditional statement (if not q, then not p) is true when the original statement is true.



So, the contrapositive of the statement is

if no fuzzles are lumpy, then no wuzzle is grumpy. (E)



Think about it. If 1 wuzzle is grumpy, then you know you have some lumpy fuzzles, right? But what if no fuzzles were lumpy? Then, it would be impossible to have grumpy wuzzles, because a grumpy wuzzle ensures a lumpy fuzzle.



So, keep your fuzzles smooth and you'll have some happy wuzzles.

Words to live by
?
2009-08-01 20:27:22 UTC
E. If no fuzzle is lumpy, then no wuzzles can be grumpy. (If a wuzzle WAS grumpy, then some fuzzles would have to be lumpy, according to the rule.)
birchett
2016-12-17 14:23:05 UTC
Fuzzle Wuzzle
railbuff
2009-08-01 20:25:06 UTC
d


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