Theory : - Given y = f(x) ...and to find area covered by the curve y with x axis between point x=a and x=b is ...just the value of integration :-
Limit of x from a---> b [ y.dx ]
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1) limit of x from 1 to 4 [ x.dx ] = limit of x from 1 to 4 [ x^2/2 ] = 16/2 - 1/2 = 15/2 ans .
2) limit of x from 2 to 3 [ 2x / (x^2 - 3 ) dx ] = limit of x from 2 to 3 [ ln(x^2-3) ] = ln ( 6 ) ans .
Note :- Integration of 2x/(x^2-3) is calculate by substituting x^2-3 as t
So it becomes 2x.dx / (t) .. and t = x^2-3 So dt/dx = 2x Hence 2x.dx = dt
Therefore ... dt/t =====> ln(t) ..and hence ln(x^2-3)
3) limit of x from 0 to 2 [ (e^x + 2).dx ] = limit of x from 0 to 2 [ e^x + 2x ] = [ e^2 + 4 - 1 ] = [e^2 +3]
Note :- Integration of e^x = e^x
4) limit of x from 1 to 3 [ 2x^3 -4x + 7 ] = limit of x from 1 to 3 [ x^4/2 - 2x^2 + 7x ]
============================= after putting limit [ 3^4/2 - 2*3^2 + 7*3 - ( 1/2 - 2*1 + 7 ) ]
=============================ans is 87/2 - 11/2 = 38
I hope it is clear now....if not then ask further
Regard
Yagya