I just want to make sure that I calculated the surface area correctly?

Question

I did some experiment in the lab report, as I cut agar into pieces and I have to measure and do some calculations:

so can you calculate the surface area for me for each block, thanks in advance

Block 1, 1x1x1 cm3
Block 2, 1x1x0.5 cm3
Block 3, 1x0.5x0.5 cm3
Block 4, 0.5x0.5x0.5 cm3
Block 5, 0.5x0.5x0.25 cm3

I want to ask something esle if you cam asnwer it, I am required to do some graph after I measue the volume of each one and the surface area of each one, how am I going to do the graph and mark it? because the teacher told me that Ihave to divid the surface area on volume???

Thanks YOU VERY VERY MUCH

Answer 1

1+1+1+1+1+1 = 6 cm^2

1+1+0.5+0.5+0.5+0.5 = 4 cm^2

0.5+0.5+0.5+0.5+0.25+0.25 = 3 cm^2

0.25+0.25+0.25+0.25+0.25+0.25 = 1.5 cm^2

0.25+0.25+0.125+0.125+0.125+0.125 = 1 cm^2



I think for the graph, you should compute the volume of each block ( you can do that - just multiply the lengths of the three sides you gave) and then mark for each block the dot in the x-y-area where



x is the surface area

y is the volume



Hope that helps ...

Answer 2

The formula for the surface area A of a rectangular block is



A = 2(LW + WH + LH)



where L is the length, W is the width, and H is the height. So the 1×1×1cm³ block has surface area



2(1*1 + 1*1 + 1*1)cm² = 6 cm²



The others are calculated similarly.



I'm not sure what you're asking in your second question. One sometimes speaks of a surface-area-to-volume ratio. Since the formula for the volume V of a rectangular block is V = LWH, we can write a formula for this ratio:



A / V = 2(LW + WH + LH) / LWH = 2[(1/H) + (1/L) + (1/W)]



For a fixed V, the rectangular block with the smallest A (and hence, with the smallest surface-area-to-volume ratio) is a cube.



Ask your teacher to clarify.

Answer 3

part of a prism is flow sectional section x length, so specific you had that staggering. For the exterior part of the prism, there are 2 triangular faces, and 3 oblong The triangles are the section you already worked out the three rectangles could be expressed by using the fringe x length floor section = 2xcross area + (perimeter x length)