What are the slope x and y values for the following: y = - (5/2) x?

Question

This is part of a Trigonometry question, but I can't figure out the main question without getting this first portion which is finding the x and y values of the slope. Any help would be greatly appreciated!

Answer 1

Slope = -5/2

x and y values are infininte. Subst. in any number for x and find y



(0,0), (2, -5), (-2,5), etc.

Answer 2

y = - (5/2) x

This is the equation of a straight line that that passes through the origin and rises as the line moves from the right to the left. This is because the slope is negative.



As you move from the origin (0,0) two units to the point (-2,0) and from there directly upward 5 units to the point (-2,5), you have fond a second point on the line. Draw a line between (0,0) and (-2,5) and extend it forever in both directions. This line has a slope of -5/2. The +5 is the change in y and the -2 is the change in x.



Slope = change in y divided by change in x.

Answer 3

the slope is -5/2. slope is "rise/run", or y/x.

thus, the y-value can be either 5 or -5, and the x-value can be either 2 or -2 (due to the ambiguity of the negative sign).



the only possible combinations are the (x= 2, y= -5) pair, or the (x= -2, y= 5).

Answer 4

THE SLOPE IS THE -(5/2)



SINCE SLOPE IS RISE OVER RUN THE 5 IS THE Y AND THE 2 IS THE X

Answer 5

this equation is in slope-intercept form (y = mx + b where m = slope and b = y intercept); therefore:



slope = -5/2

y-intercept (x = 0) = 0

x-intercept (y = 0) = 0



This means the line crosses at point (0,0) or, the origin.



Slope is defined as rise over run, or change in y divided by change in x, so your change in y is -5 and change in x is 2, or change in y is 5 and change in x is -2 (depending on direction).



Hope this helps! :)