Question:
grade nine math? equation of a line?
Hugs&Kissesxo
2008-10-30 19:20:59 UTC
i need help with a question like this:

perpendicular to 3/2x + 2 = y and has a y-intercept of -2

thanks in advanced
21 answers:
2008-10-30 19:42:26 UTC
hello solving this math problem is this:



remeber when two lines are perpendicular..... " two lines are perpendicular when their slopes equal with -1 (k1 multiply k2 =-1)



and your y-intercept is (0,-2)



well you have the first euqation of the line and has the slope of 3/2=k1

so use the formula on top (k1 mult. k2 =-1)

thua subsitut k1 with 3/2



you will have (3/2mult k2=-1)

than divide both sides by 3/2

you ll have k2=-1over 3/2

k2=-2/3 so this is your slope for second equation of line



now you have the y-intercept (0,-2)



remeber also the euation of th e line through one pine is

y-y1=k2(x-x1)

subst. your y int.

y-(-2)=-2/3(x-0)

y+2=-2/3x



and finally there it is your answer y=-2/3x -2







for two line parallel is k1=k2



yur poins (0,0)



so y-0=3/2(x-0)



and the answer is y=3/2x



i hope its going to be helpful for you
greengo
2008-10-30 19:35:27 UTC
To find the perpendicular line, that means it is at a 90 degree angle. The slope of the line is the same, just opposite (draw an "X" and you will see what I mean) the slope is the same but it is negative reciprocal. Therefore, in the original equation, the slope is 3/2. The negative reciprocal is -2/3. If the y intercept is -2, then the equation must be -2/3x + -2 = y



For the second equation, all you have to do is realize that "b" = 0 because it passes through the origin, which is 0,0

So, your equation is y= 5/3x and that is it.



I had to ask my 11 year old for the answer, lol, I don't remember this
Austin
2008-10-30 19:26:14 UTC
What math are you in, this seems like Algebra 1.

I'm in 9th grade too!

So here is the answers and how I got them

A line that is perpendicular to 3/2x +2=y and has a y-intercept of -2, the lines so since the equation above already has 2 as a y intercept, and you need -2 and the y-intercept, you must swap the numerator and denominator, and change the sign (in this case positive to negative). So the equation would be -2/3x-2=y



Parallel to y=5/3x-2/3 and passes through the origin would be y=5/3x + 0, or a more proper way of writing it just y=5/3x



Hope this Helps, don't be afraid to ask with anymore questions.
twatllama
2008-10-30 19:25:52 UTC
Am I about to do your homework for you?



Perpendicular is a fancy way of saying 90 degree angles exist everywhere between two connecting lines, so it looks like a +. Y intercept -2 just means that your new line intersects the Y axis at point -2. So your new equation should be the negative slope of the first line, minus 2. So Y = -3/2x - 2



Parallel means the slopes are the same, and passes through the origin means the Y intercept is 0. So try that one by yourself.
2008-10-30 19:26:12 UTC
OO! I'm learning this now, but I'm in 8th. For the first question, 3/2x + 2 = y, you do this:



write it in y=mx+b form

y = 3/2x + 2/1, right?



draw a graph, and move across 3 and up 2 spaces. make a point there. then, from that point, move across 2 more points and up 1 more point. write an equation with a line perpendicular to that. i hope you know what perpendicular means, b/c i forgot. i know that if you need to write an equation parallel to this, you just need to keep the slope the same, which is b. so make the slop in the next equation 2 also. good luck with your homework!
2008-10-30 19:30:04 UTC
The formula for slope is y= mx+b

to find the perpendicular line to a slope,

take the reciprocal of the m part of the equation & make is negative.

ie. if m=1/3, then the reciprocal would be m=-3/1.



For the // lines, have the same slope, so as long as you keep m original, you can do what ever you want with the b.
2008-10-30 19:25:58 UTC
If a line is parallel to another line, it will have the same slope. It it passes through the origin, the y-intercept will also be at the origin.



If a line is perpendicular to another line, its slope will be the negative reciprocal of the line it is perpendicular to.



You can find the equations of both lines with the substantial amount of information I've given you. Other than that, you need to do your own homework and I've given you plenty of hints, so that won't be hard.
eclaire211
2008-10-30 19:28:29 UTC
1. y=-2/3x-2



To find a perpendicular line, you change the slope to the opposite reciprocal of the original slope (i.e. 5/4 becomes -4/5 or -6/7 becomes 7/6).



2. y=5/3x



Two parallel lines have the same slope, so just keep the same slope for your answer.
cool guy15
2008-10-30 19:28:10 UTC
remember, if you want to find the perpendicular of a line, always try to isolate the x by itself. so you would subtract 2 so you would get

3/2x =-2. then you multiply it by 2/3 so 3/2 would cancel. -2 times 2/3= - 1.3. -1.3 is the perpendicular slope. to find the b, plug -2 into the equation and you should get it fairly easily. then put it all together.

hope it helps..
?
2016-09-28 13:22:41 UTC
i've got finished this final 3 hundred and sixty 5 days, and that they are very easy. i'm presently engaged on an essay, so i can not help you, yet on your math textual content textile e book, there could be little mini classes in the previous each and each ingredient is defined, and that they'll practice you examples for each and all the solutions you're searching for.
Jon
2008-10-30 19:25:27 UTC
if it is perpendicular, then the slope is -2/3

so it is y=-2/3x-2



if it is parellel, then is has the same slope

and the y intecept is 0

so it is y=5/3x
2008-10-30 19:24:10 UTC
if you have a graphing calculator type it in and it will give you the answer



the equation of a line= m = (y2 - y1) / (x2 - x1)
LvR-C
2008-10-30 19:25:05 UTC
I'm in 8th grade, but I take 9th grade math. And I still don't get this.
2008-10-30 19:23:10 UTC
4?
giants455
2008-10-30 19:24:32 UTC
y=-2/3x+2







y=5/3x
sage
2008-10-30 19:23:59 UTC
use a graphing calculater lol maybe google can find some online calculater sumwere
2008-10-30 19:25:02 UTC
it's very hard to picture.. we need more info than that
Anonymousish
2008-10-30 19:24:03 UTC
this is definitely not honors geometry.
Glenn
2008-10-30 19:23:50 UTC
tch...i learned that in 7th grade
2008-10-30 19:23:22 UTC
if i wasnt failing geometry honos i'd help u out



https://answersrip.com/question/index?qid=20081030190701AAv6pUB
ogmak31
2008-10-30 19:22:54 UTC
lol


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