The times mentioned are not the exact answers.
Let x be the number of minutes so that the hour hand and the minute hand overlaps after a time of A o'clock.
Thus A = 0,1,2,3, ... ,10
Then at A o'clock, the hour hand is at the number A.
Also, if the minute hand is 12 times faster than the hour hand. Thus if the minute hand had traveled for x, then the hour hand had traveled for x/12
The equation is now:
5A + x/12 = x
5A = 11x/12
x = 60A/11 ... this is the number of minutes when they would overlap
thus at 1:00 (A = 1)
x = 60/11 ≈ 5.454545 minutes
thus the exact times are:
1 : 05 & 5/11 min = 1 : 05 min 27 3/11 seconds
2 : 10 & 10/11 min = 2 : 10 min 54 6/11 seconds
3 : 16 & 4/11 min
4 : 21 & 9/11 min
5 : 27 & 3/11 min
6 : 32 & 8/11 min
7 : 38 & 2/11 min
8 : 43 & 7/11 min
9 : 49 & 1/11 min
10:54 & 6/11 min
the next time they would overlap is again at 12:00 .
just convert the rest of the fractional part of the minutes to seconds (multiply by 60 .)