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Question

Some games of chance rely on tossing two dice. Each die has six faces, marked with 1, 2, . . . , 6 spots called pips. The dice used in casinos are carefully balanced so that each face is equally likely to come up. When two dice are tossed, each of the 36 possible pairs of faces is equally likely to come up. The outcome of interest to a gambler is the sum of the pips on the two up-faces. Call this random variable .
Reference: 4.56

4.56c Several bets in craps lose if a 7 is rolled.
If any outcome other than 7 occurs, these bets either win or continue to the next roll. What is the probability that anything other than a 7 is rolled?
Give your answer to 3 decimal places.
Fill in the blank:
p( not 7)

Answer 1

36 possible outcomes

6 of them total 7; 30 of them do not



so p(not 7) = 5/6 = 0.833



:-)

Answer 2

Michelle,

there are 36 possible pairs. How many of these add up to 7? Such as 6 and 1, 5 and 2 and so on. List them all, count them. How many? Divide by 36, the number of all possible pairs. This is the probability of p(7).



p(not 7)=1-p(7)

Answer 3

I'm studying trig right now and getting my formulas mixed up, but I believe it is P(E)+P(not E)=1 thus P(not E)=1-P(E) hope that helps so that means 1-the probability that P(7) occurs.