Question:
Math Help Please!! Limits question!?
Alexandra
2012-09-22 09:32:54 UTC
The question is to use the properties of limits to help decide whether the limit exists and find it's value if it does.

lim as x approches infinity

8x²- 8x^4
__________
5² - 6x - 6

The thing that i'm not sure about is, i think your supposed to devide everything by the highest exponant, but if you do that then the bottom is zero and then i don't know what that means. can anyone help? thanks
Three answers:
Joseph
2012-09-22 09:48:15 UTC
You should write it properly because you wrote 5² at the bottom and I guess it's 5x² instead. In this case it's quite simple. You cellect the x with maximum exponent and then consider that all terms with x at some exponent at denominator go to zero when x goes to ∞. So let's proceed this way:



lim(x→∞) x⁴*[8/x² - 8]/x²*[5 - 6/x - 6/x²] = lim(x→∞) x²*[8/x² - 8]/[5 - 6/x - 6/x²]



Like we said, when when x goes to ∞ all terms like 8/x², 6/x, etc. go to zero, so you're left with:



lim(x→∞) x²*[0 - 8]/[5 - 0 - 0] = lim(x→∞) x²*(-8/5) = -∞
Vahl'Dra
2012-09-22 16:41:43 UTC
umm... 2+2=5!



edit: 5 times squared minus 8 times something 4 over 5 squared minus 6 times minus 6...

uhh.. yupp you're screwed..
Paul
2012-09-22 16:34:25 UTC
Go to Khan Academy, that'll help you for sure. It's online. :)


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