integers!!!!!?

Question

what is the largest positive and unique integer that is divisable by 1 through 18 inclusive with no remainder?
thanks

Answer 1

the largest one would be infinitely large. if you're looking for the least, it's:



2*2*2*2*3*3*5*7*11*13*17 = 12,252,240



The numbers that we multiplied are the prime factors of the numbers from 1 to 18.

Answer 2

18 factorial (18x17x16x15, etc)...not sure what you mean by "unique"



But, you can multiply that by any # to get a larger one. I'm not sure I fully understand the question or if the question actually makes sense.



Wait...do you mean the smallest #? If so, that would be 18x17x8x5x7x13x11=12,252,240.



(start w/ the largest which is 18 & then look at each of the smaller ones to see which still need to be covered - so 17 yes, but for 16, you only need 8 since 2 is covered wi/ 18 (2 x9); for 15, you only need 5 (since 3 is covered wi/ 18 2x3x3))

Answer 3

If you multiplied 1 through 18, you'd have the smallest positive integer. But you can always, double it, triple it, and so on. There is no largest.

Answer 4

I guess u mean the least integer and it is:



2*3*2*5*2*7*3*5*11*13*2*17

Answer 5

inifinity