math homework help algebra 1...?

Question

okay heres the questions much thanks to evryone who answers ...
for questions 1-8 solve each equation for y

question #1) y + 2x = 5
question #2) y - 6x = -1
question #3) y + 4x = 3
question #4) 2y + 4x = 8
question #5)3y - 5x = 9
question #6) 4y + 3x =7
question #7) 5x + 4y = 4
question #8) 2x + 7y = 4
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okay for questions 9-14 solve each rquation for the variable in capitol letters
question #9) Z - a = y
question #10) ax + bY = c
question #11) a = p + prT
question 12) s = c + Rc
question 13) m/n = P/q
question 14) Y - b/m = x

okay i wont [ut any more thanks to everyone who helps i really have troubles in math and i need to get that grade up to stay in sports so that means i need to turn in homework

Answer 1

y + 2x = 5; y = -2x + 5

y - 6x = -1; y = 6x - 1

y + 4x = 3; -4x + 3

2y + 4x = 8; 2y = -4x + 8; y = -2x = 4

3y - 5x = 9; 3y = 5x + 9; y = 5/3 x + 3

4y + 3x =7; 4y = -3x + 7; y = -3/4 x + 7/4

5x + 4y = 4; 4y = -5x + 4; y = -5/4 x + 1

2x + 7y = 4; 7y = -2x + 4; y = -2/7 + 4/7



It is just like solving an equation like: x + 5 = 11, you move the 5 to the other side by doing the opposite.



so y + 2x = 5, to solve for y you subtract 2x from both sides.

Answer 2

I know this answer looks long, but please read it; it is very informative!

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Ok, all you have to do is, step by step, isolate the variable so it is completely by itself on one side of the equation.



I'll work through #1 with you:



y + 2x = 5



Now, this one is pretty simple. It only requires one step. On the side of the equal sign that contains y, there is a +2x. To isolate y, the +2x has to go. The only way to do that is to subtract it. And remember, to keep the equation equal, what you do to one side of the equation, you must do to the other side. Therefore, you must subtract 2x from both sides. Now, you took the 2x away from the left side, but you also put it onto the right side. Therefore, you're equation will be:



y = -2x + 5

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Here; I'll help you with #8. It's a tad more complicated.



2x + 7y = 4



Now, first, just like above, your first step to isolating y is to remove the 2x. So, just as I did above, I will subtract 2x from both sides. I now have...



7y = -2x + 4



I am not finished yet however! there is still a 7 attached to that y. Because the 7 and y are multiplied, I must divide it to isolate the y. Therefore, both sides must be divided by 7. Now the y is completely isolated, and the final equation is as such:



y = -2/7x + 4/7

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Use this same method to answer 9-14.



Example - #12:



c + Rc = s



First, remove c. Do this by subtracting from both sides. Your equation now is:



Rc = s + c



Next, remove the other c by dividing both sides by c. Your equation will then be:



R = s/c + c/c



Now because all the c's are the same number, and a number divided by itself is 1, the final equation will turn out as:



R = s/c +1





Hope I was of help!! If you need another demonstration, please ask!

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PS: oxymoron1992 - I totally agree with you. We got tests all the time in algebra 1. These tests take up more of your grade than the homework. Also, I am currently in geometry, and we are using algebra 1 material quite frequently.

Answer 3

For a number of those issues you prefer to choose and label a variable. In concern one they write on the topic of the size in terms of the width. permit x = the width on the grounds that we are instructed the size is one unit extra suitable than the width we then have: x + a million = the size. by way of fact the part of a rectangle is given via length situations width (or equivalently width situations length), we get the equation: (x)(x + a million) = 30 via the distributive property we get x^2 + x = 30 placing one ingredient to 0 x^2 + x - 30 = 0 element (x +6)(x-5) = 0 subsequently x + 6 = 0 or x - 5 = 0 x = -6 or x = 5. on the grounds that we are speaking some distance we are able to brush aside the unfavorable answer. So the width (which we categorized as x) is 5 gadgets, and the size (which we categorized as x + a million) is 6 gadgets. For concern 2, on the grounds that we are speaking approximately consecutive weird and wonderful integers, (ex 3, 5, 7, 9, 11), all of us understand they might desire to be separated via two gadgets each. permit x = the 1st consecutive weird and wonderful integer Then x + 2 is the 2d consecutive weird and wonderful integer. Product implies multiplication, so (x)(x + 2) = 195 x^2 + 2x = 195 x^2 + 2x - 195 = 0 (x + 15)(x - 13) = 0 x = - 15 or x = 13 the 1st pair of recommendations is -15 and -15 + 2 = -13 the 2d pair of recommendations is 13 and 13 + 2 = 15

Answer 4

You know, I hate it when people come on Y! A and ask people to do their homework for them. I hate it even more when people do that homework for them. I understand you may need math help and you want to keep your grades up, but I think you should have asked for help to learn how to do the problems instead of asking for the answers.



I'm sure you're probably just annoyed with me for giving this whole do-your-own-homework thing, but think about it -- if you don't learn how to do these problems, you probably won't do too well on the test. And the test affects your grade just as much as the homework. Plus, you're going to need to know how to do this stuff in Geometry (depending on your school's curriculum) and Algebra II.



Also, if you're having trouble, you should ask your teacher for help. Teachers are meant to teach, and to help students learn.



I hope my little speech here at least made you think about it. And if you need help understanding how to solve the problems, let me know and I'll be glad to help you.

Answer 5

Would it benefit you to learn how to do this? Yes, it would and I know you can! Once you get the concept, it will go good for you. And then on the tests you will do well also. Good Luck!