Two trigonometry problems I need help with?

Question

Problem 1:
Your in a school parking lot and measuring 30 degrees to the top of the building, you walk forward 30 feet and measure to the top of the building again and get 40 degrees. What is the height of the building?

Problem 2:
Your on a street hill and measure a brick on a building on the street and get 25cm on the adjacent leg and 12cm on the opposite leg. What is the angle of the street hill?

How do you do these? Please provide examples! Thank you!

Answer 1

Hi,



Problem 1:

You're in a school parking lot and measuring 30 degrees to the top of the building, you walk forward 30 feet and measure to the top of the building again and get 40 degrees. What is the height of the building?



x tan 30º = (x - 30) tan 40º



.5774x = .8391x - 25.173



-.2617x = -25.173



x = 96.19 feet away from the building



. . . . . . . height

tan 30º = ----------

. . . . . . . 96.19



height = 55.54 feet <==ANSWER



Problem 2:

You're on a street hill and measure a brick on a building on the street and get 25cm on the adjacent leg and 12cm on the opposite leg. What is the angle of the street hill?



. . . . . . 12

tan A = ------

. . . . . . 25



A = 25.64º <==ANSWER



I hope that helps!! :-)

Answer 2

I am barely taking Algebra 2 but cant you just set up the problems using proportions to estimate the height of the building.

Answer 3

2) tan^-1(12/25) is answer.