Multiplying negative square roots: Help please?

Question

hello everyone!
i'm working on my college algebra homework and i am having trouble with this question. i am not looking for just the answer but for someone who is willing to explain it. thanks i greatly appreciate it, 10 pts to the first correct and helpful answers

Perform the indicated operation. Simplify your answer
squareroot(-9) by squareroot (-63)

simply you are multiplying the squareroot of -9 by the squareroot of -63. obviously this has to do with imaginary numbers and i which i am confused about. thanks again!

Answer 1

squareroot(-9) * squareroot (-63)



= squareroot(9 * -1) * squareroot (63 * -1)



square root(-1) = iota



= sqaure root (9) iota * square root (63) iota



= 3 iota * sqaure roor ( 3 * 3 * 7) iota



because 63 = 3 * 3 *7



= 3 iota * 3 iota * sqaure root( 7 )



because square root (3 * 3 ) = 3



= 9 iota square * sqaure root (7)



since iota square = -1



= -9 * square root(7)



that is the final answer

Answer 2

Multiplying Negative Square Roots

Answer 3

it doesn't really have to do with imaginary numbers

when you multiply a square root by a square root as in sqrta*sqrtb you get sqrt(a*b)so all you need to do is multiply -9 by -63 and then find the square root which is 9sqrt7

Answer 4

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RE:

Multiplying negative square roots: Help please?

hello everyone!

i'm working on my college algebra homework and i am having trouble with this question. i am not looking for just the answer but for someone who is willing to explain it. thanks i greatly appreciate it, 10 pts to the first correct and helpful answers



Perform the indicated...

Answer 5

-sqrt(5) * -sqrt(3) = sqrt(15) Assuming you mean "square root of negative 5" which is sqrt(-5) sqrt(-5) = i*sqrt(5) sqrt(-3) = i*sqrt(3) i^2 * sqrt3sqrt5 = -sqrt(15) Note that the identity sqrt(a)sqrt(b) = sqrt(ab) does NOT extend to the negative numbers.

Answer 6

FYI: all you ever need to know about i:

i = sqrt (-1)

i^2 = -1

i^3 = i * i^2 = i(-1) = -i

i^4 = i^2 * i^2 = -1(-1) = 1

Now to your problem.

sqrt(-9) = sqrt(-1) * sqrt(9), right? So it simplifies to 3i.

sqrt(-63) =sqrt(-1) * sqrt(9) * sqrt(7). So it simplifies to 3i(sqrt7)

Therefore, 3i(3i)(sqrt 7) is where you now stand.

and further, 3(3)(i)(i)(sqrt 7)

equals, 9i^2(sqrt 7)......remember i^2 = -1

and 9(-1)(sqrt7) = -9sqrt7

Answer 7

-3squared = 3x3x-1= -9

(-3)squared = -3x-3= 9



same with all other numbers, its all about the ()

Answer 8

i=sqrt-1

so i^2=-1

so 9i*63i=567i^2

=-567

Answer 9

answer is always one