help.. please.?

Question

1.) Write the equation of the parabola with focus at (0,6) and directrix y = -6.

2.)Name the center and the radius of the circle represented by the equation (x – 5)^2 + y^2 = 16. Be sure to give 2 answers, the coordinate of the center and the value of the radius.

3. write the equation of the ellipse with foci at (+/-2, 0) and x-intercepts at +/-5.

Answer 1

Vertex = (0,0) , it's between the focus and directrix.



4py = x^2

4p + 0 = 6

p = 3/2

6y = x^2

y = x^2 / 6



2. center: (5,0)

radius = 4



3. Assume your x-intercepts are the vertices also, otherwise the equation cannot be find.



x^2 / 25 + y^2 / b^2 = 1



4 = 25 - b^2

b^2 = 21

b = +/- sqrt 21



x^2 / 25 + y^2 / 21 = 1

Answer 2

1.



y = (1 / (4p))x^2



p = 6 (y-value of focus)



y = (1/24)x^2







2.



(x - h)^2 + (y - k)^2= r^2



(x - (+5))^2 + (y - 0)^2 = 4^2



center is (5, 0) and radius is 4.

Answer 3

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Answer 4

not a clue